WebCorrect option is A) In ADE and ABC ∠ADE=∠ABC (As DE∥BC Corresponding angles) ∠AED=∠ACB (As DE∥BC Corresponding angles) ∠DAE=∠BAC (common angle) ∴ ADE∼ ABC by AAA similarity. If two triangles are similar, then their corresponding sides are proportional. ⇒ ABAD= BCDE 73= 14x x= 73×14⇒x=6 Solve any question of Triangles … WebIn a right triangle ABC, right angled at B, BC=15cm, and AB=8cm. A circle is inscribed in triangle ABC. The radius of the circle is : A 1cm B 2cm C 3cm D 4cm Medium Solution Verified by Toppr Correct option is C) Using Pythagoras theorem in ABC (AB) 2+(BC) 2=(AC) 2 (15) 2+(8) 2=(AC) 2 ⇒(AC) 2=225+64=289 ⇒AC=17cm Now inradius r= sΔ

Given AD B D ABD ABC

WebDC = BC - BD DC = 20 - 7 DC = 13 Ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights. ∴ A (∆ ABD) A (∆ ADC) AX BD AX DC A (∆ ABD) A (∆ ADC) = 1 2 × AX × BD 1 2 × AX × DC ∴ A (∆ ABD) A (∆ ADC) BD DC A (∆ ABD) A (∆ ADC) = BD DC ∴ A (∆ ABD) A (∆ ADC) A (∆ ABD) A (∆ ADC) = 7 13 WebBC = BD + DC ...[B - D - C] DC = BC - BD DC = 20 - 7 DC = 13. Ratio of areas of two triangles is equal to the ratio of the products of their bases and corresponding heights. ∴ `"A(∆ … gold leaf smoke shop puerto vallarta

In ∆Abc, B – D – C and Bd = 7, Bc = 20 Then Find …

WebGiven AB, BC and AC are tangents to the circle at E, D and F. BD = 30 cm and DC = 7 cm and ∠BAC = 90° Recall that tangents drawn from an exterior point to a circle are equal in … WebIn the given figure, BC ⊥ AB, AD ⊥ AB, BC = 4, AD = 8, then find AABCAADBA(∆ABC)A(∆ADB) - Geometry Advertisement Remove all ads Advertisement Remove all ads WebSep 11, 2024 · In an equilateral triangle ABC, D is a point on side BC such that BD = 1/3 BC then AB2 = Q8. In ABC, ∠B = 90°, AB = 12 cm and AC = 15 cm. D and E are points on AB and AC respectively such that ∠AED = 90° and DE = 3 cm then the area of ADE is Q9. If an angle is equal to one-fifth its compliment, then the angle is: goldleaf software